uva 10140 素数筛选(两次)

#include<iostream>
#include<cstring>
#include<cmath>
#include<cstdio>
using namespace std;

bool flag[50010];
int prime[8000];
bool r[1000010];
int num;
void Init()
{
    int i,j;
    num=0;
    memset(flag,true,sizeof(flag));
    flag[1]=flag[0]=0;
    for(i=2;i<50000;i++)
    {
        if(flag[i]) prime[num++]=i;
        for(j=0;j<num && i*prime[j]<50000;j++)
        {
            flag[i*prime[j]]=false;
            if(i%prime[j]==0) break;
        }
    }
}

int main()
{
    Init();
    long long a,b,up,mina,minb,maxa,maxb,min,max,i,j,k;
    while(cin>>a>>b)
    {
        if(a==1) a++;//a=1的情况
min
=20000000; max=0; memset(r,true,sizeof(r)); for(i=0;i<num && prime[i]*prime[i]<=b;i++) { k=a/prime[i]; if(k*prime[i]<a) k++; if(k<=1) k++; while(k*prime[i]<=b) { r[k*prime[i]-a]=false; k++; } } j=0;up=-1; for(i=0;i<=b-a;i++) { if(r[i]) { if(up==-1) up=i; else { if(min>i-up) { min=i-up; mina=up; minb=i; } if(max<i-up) { max=i-up; maxa=up; maxb=i; } up=i; } } } if(max==0) printf("There are no adjacent primes. "); else printf("%lld,%lld are closest, %lld,%lld are most distant. ",mina+a,minb+a,maxa+a,maxb+a); } return 0; }
原文地址:https://www.cnblogs.com/xiong-/p/3222990.html