Description
Age Sort：You are given the ages (in years) of all people of a country with at least 1 year of age. You know that no individual in that country lives for 100 or more years. Now, you are given a very simple task of sorting all the ages in ascending order.
Input
There are multiple test cases in the input file. Each case starts with an integer n (0 < n ≤ 2000000), the total number of people. In the next line, there are n integers indicating the ages. Input is terminated with a case where n = 0. This case should not be processed.
Output
For each case, print a line with n space separated integers. These integers are the ages of that country sorted in ascending order. Warning: Input Data is pretty big (∼ 25 MB) so use faster IO.
Sample Input
5
3 4 2 1 5
5
2 3 2 3 1
0
Sample Output
1 2 3 4 5
1 2 2 3 3
解题思路：首先确定程序循环条件，然后然按照题意先输入n个数字，并把它存在一个数组中，再用sort函数将它排序（sort函数存在于头文件<algorithm>中，它是按从小到大的顺序排序的）排 好序之 后就要用for循环语句将它输出来，这时要注意空格的输出，可以这样控制空格的输出（首先给定一个first,并将它赋值为1，如果first为1就把它赋值为0；否则就输出空格， 这样就可以保证不 会输出多余的空格。）
程序代码：
#include <stdio.h>
#include <algorithm>
using namespace std;
const int maxn=2000000;
int a[maxn];
int main ()
{
int n;
while(scanf("%d",&n)&&n)
{
int first=1;
for(int i=0;i<n;i++)
scanf("%d",&a[i]);
sort(a,a+n);
for(int k=0;k<n;k++)
{
if(first)
first=0;
else
printf(" ");
printf("%d",a[k]);
}
printf("
");
}
return 0;
}