MySQL2

一、主键、外键补充
  create table tb1用户表(
    id int not null auto_increment primary key,
    name char(10),
    department_id int,
    p_id int,
    constraint fk_1 foreign key (department_id,p_id) references tb2(tid,xid)
  )engine=innodb default charset=utf8;


  补充:主键
    一个表只能有一个主键
    主键可以由多列组成


  补充:外键 ?
  CREATE TABLE t5 (
    nid int(11) NOT NULL AUTO_INCREMENT,
    pid int(11) not NULL,
    num int(11),
    primary key(nid,pid)
  ) ENGINE=InnoDB DEFAULT CHARSET=utf8;

  create table t6(
    id int auto_increment primary key,
    name char(10),
    id1 int,
    id2 int,
    CONSTRAINT fk_t5_t6 foreign key (id1,id2) REFERENCES t1(nid,pid)
  )engine=innodb default charset=utf8;

二、数据行


  insert into tb1(name,age) values('alex',18);
  insert into tb1(name,age) values('alex',18),('egon',19),('yuan',20);    可以同时插入多条数据

  update tb1 set name='root' where id > 10

  select * from tb;
  select id,name from tb;

三、对于自增补充:
  desc t10;    查看该表的创建方式:列名,是否可以为空,数据类型,是否为主键,是否为自增

  show create table t10;
  show create table t10 G;


  alter table t10 AUTO_INCREMENT=20;    修改下次开始自增的值

  MySQL: 自增步长
    基于会话级别:
      show session variables like 'auto_inc%'; 查看全局变量
      set session auto_increment_increment=2; 设置会话步长
      # set session auto_increment_offset=10;
    基于全局级别:
      show global variables like 'auto_inc%'; 查看全局变量
      set global auto_increment_increment=2; 设置会话步长
      # set global auto_increment_offset=10;


  SqlServer:自增步长:
    基于表级别:
      CREATE TABLE `t5` (
        `nid` int(11) NOT NULL AUTO_INCREMENT,
        `pid` int(11) NOT NULL,
        `num` int(11) DEFAULT NULL,
        PRIMARY KEY (`nid`,`pid`)
      ) ENGINE=InnoDB AUTO_INCREMENT=4, 步长=2 DEFAULT CHARSET=utf8

      CREATE TABLE `t6` (
        `nid` int(11) NOT NULL AUTO_INCREMENT,
        `pid` int(11) NOT NULL,
        `num` int(11) DEFAULT NULL,
        PRIMARY KEY (`nid`,`pid`)
      ) ENGINE=InnoDB AUTO_INCREMENT=4, 步长=20 DEFAULT CHARSET=utf8


四、 今日内容:
0. 唯一索引:约束该列中数据唯一
  create table t1(
    id int ....,
    num int,
    xx int,
    unique 唯一索引名称 (列名,列名),    联合唯一
    constraint ....
  )
    #
      1 1 1
      2 1 2
  PS:
    唯一索引:
    约束不能重复(可以为空)
      PS: 主键不能重复(不能为空)
    加速查找

1. 外键的变种

a. 用户表和部门表

  用户:
  1 alex 1
  2 root 1
  3 egon 2
  4 laoyao 3

  部门:
  1 服务
  2 保安
  3 公关
===》 一对多
b. 用户表和博客表
  用户表:
  1 alex
  2 root
  3 egon
  4 laoyao
  博客表:
    FK() + 唯一
  1 /yuanchenqi/ 4
  2 /alex3714/ 1
  3 /asdfasdf/ 3
  4 /ffffffff/ 2

===> 一对一

  create table userinfo1(
    id int auto_increment primary key,
    name char(10),
    gender char(10),
    email varchar(64)
  )engine=innodb default charset=utf8;

  create table admin(
    id int not null auto_increment primary key,
    username varchar(64) not null,
    password VARCHAR(64) not null,
    user_id int not null,
    unique uq_u1 (user_id),
    CONSTRAINT fk_admin_u1 FOREIGN key (user_id) REFERENCES userinfo1(id)
  )engine=innodb default charset=utf8;


c. 用户表(百合网) 相亲记录表

示例1:
  用户表
  相亲表

示例2:
  用户表
  主机表
  用户主机关系表
===》多对多

  create table userinfo2(
    id int auto_increment primary key,
    name char(10),
    gender char(10),
    email varchar(64)
  )engine=innodb default charset=utf8;

  create table host(
    id int auto_increment primary key,
    hostname char(64)
  )engine=innodb default charset=utf8;


  create table user2host(
    id int auto_increment primary key,
    userid int not null,
    hostid int not null,
    unique uq_user_host (userid,hostid),
    CONSTRAINT fk_u2h_user FOREIGN key (userid) REFERENCES userinfo2(id),
    CONSTRAINT fk_u2h_host FOREIGN key (hostid) REFERENCES host(id)
  )engine=innodb default charset=utf8;


2. SQL语句数据行操作补充
  create table tb12(
    id int auto_increment primary key,
    name varchar(32),
    age int
  )engine=innodb default charset=utf8;


  insert into tb11(name,age) values('alex',12);

  insert into tb11(name,age) values('alex',12),('root',18);

  insert into tb12(name,age) select name,age from tb11;    将tb11中的数据插入到tb12

  delete from tb12;
  delete from tb12 where id !=2
  delete from tb12 where id =2
  delete from tb12 where id > 2
  delete from tb12 where id >=2
  delete from tb12 where id >=2 or name='alex'


  update tb12 set name='alex' where id>12 and name='xx'
  update tb12 set name='alex',age=19 where id>12 and name='xx'
查(重点)

  select * from tb12;      

  select id,name from tb12;

  select id,name from tb12 where id > 10 or name ='xxx';

  select id,name as cname from tb12 where id > 10 or name ='xxx';

  select name,age,11 from tb12;

其他:
  select * from tb12 where id != 1
  select * from tb12 where id in (1,5,12);
  select * from tb12 where id not in (1,5,12);
  select * from tb12 where id in (select id from tb11)
  select * from tb12 where id between 5 and 12;


通配符:

  select * from tb12 where name like "a%"
  select * from tb12 where name like "a_"


分页:

  select * from tb12 limit 10;        查看该表前10行数据

  select * from tb12 limit 0,10;      从1开始取10行数据
  select * from tb12 limit 10,10;      从11开始取10行数据

  select * from tb12 limit 20,10;      从21开始取10行数据

  select * from tb12 limit 10 offset 20;      从第21行开始读取,读取10行;

结合Python分页:
# page = input('请输入要查看的页码')
# page = int(page)
# (page-1) * 10
# select * from tb12 limit 0,10; 1
# select * from tb12 limit 10,10;2


排序:
  select * from tb12 order by id desc;         大到小
  select * from tb12 order by id asc;           小到大
  select * from tb12 order by age desc,id desc;

取后10条数据
  select * from tb12 order by id desc limit 10;

分组:

  select count(id),max(id),part_id from userinfo5 group by part_id;
聚合函数:
  count
  max
  min
  sum
  avg

**** 如果对于聚合函数结果进行二次筛选时?必须使用having ****
  select count(id),part_id from userinfo5 group by part_id having count(id) > 1;

  select count(id),part_id from userinfo5 where id > 0 group by part_id having count(id) > 1;


连表操作:

  select * from userinfo5,department5 where userinfo5.part_id = department5.id

  select * from userinfo5 left join department5 on userinfo5.part_id = department5.id
  select * from department5 left join userinfo5 on userinfo5.part_id = department5.id


# userinfo5左边全部显示
  # select * from userinfo5 left join department5 on userinfo5.part_id = department5.id

# department5右边全部显示

  # select * from userinfo5 right join department5 on userinfo5.part_id = department5.id
  
将出现null时一行隐藏

  select * from userinfo5 innder join department5 on userinfo5.part_id = department5.id


将多个(3个)表连接起来:
  select * from
    department5
  left join userinfo5 on userinfo5.part_id = department5.id
  left join userinfo6 on userinfo5.part_id = department5.id

将多个(5个)表连接起来:
  select
    score.sid,
    student.sid
  from
    score

  left join student on score.student_id = student.sid

  left join course on score.course_id = course.cid

  left join class on student.class_id = class.cid

  left join teacher on course.teacher_id=teacher.tid




select count(id) from userinfo5;



作业练习:
http://www.cnblogs.com/wupeiqi/articles/5729934.html
10-15个完成



原文地址:https://www.cnblogs.com/xingqisan/p/10950403.html