Description
You are given a car odometer which displays the miles traveled as an integer. The odometer has a defect, however: it proceeds from the digit 3 to the digit 5, always skipping over the digit 4. This defect shows up in all positions (the one's, the ten's, the hundred's, etc.). For example, if the odometer displays 15339 and the car travels one mile, odometer reading changes to 15350 (instead of 15340).
Input
Each line of input contains a positive integer in the range 1..999999999 which represents an odometer reading. (Leading zeros will not appear in the input.) The end of input is indicated by a line containing a single 0. You may assume that no odometer reading will contain the digit 4.
Output
Each line of input will produce exactly one line of output, which will contain: the odometer reading from the input, a colon, one blank space, and the actual number of miles traveled by the car.
Sample Input
Copy sample input to clipboard 13 15 2003 2005 239 250 1399 1500 999999 0
Sample Output
13: 12 15: 13 2003: 1461 2005: 1462 239: 197 250: 198 1399: 1052 1500: 1053 999999: 531440
分析：根据题目，在十进制里面去掉了4，那么也就是变成了9进制。然后因为跳过了4，那么大于4的值显然就应该减1
#include <iostream> #include <cmath> using namespace std; int main(int argc, char const *argv[]) { int number, numT; while (cin >> number && number != 0) { numT = number; int k = 0; int result = 0; while (number) { int t = number % 10; t = t >= 5 ? t - 1 : t; result += t * pow(9, k++); number /= 10; } cout << numT << ": " << result << endl; } return 0; }