205. 判断两个字符串的模式是否相同 Isomorphic Strings

Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg""add", return true.

Given "foo""bar", return false.

Given "paper""title", return true.

Note:
You may assume both s and t have the same length.


  1. public class Solution {
  2. public bool IsIsomorphic(string s, string t) {
  3. if (s.Length != t.Length) {
  4. return false;
  5. }
  6. Dictionary<char, int> set = new Dictionary<char, int>();
  7. List<int> parS = new List<int>();
  8. int num = 1;
  9. foreach(var i in s) {
  10. int val;
  11. set.TryGetValue(i, out val);
  12. if (val != 0) {
  13. parS.Add(set[i]);
  14. } else {
  15. set[i] = num;
  16. parS.Add(set[i]);
  17. num++;
  18. }
  19. }
  20. List<int> parT = new List<int>();
  21. set.Clear();
  22. num = 1;
  23. foreach (var i in t) {
  24. int val;
  25. set.TryGetValue(i, out val);
  26. if (val != 0) {
  27. parT.Add(set[i]);
  28. } else {
  29. set[i] = num;
  30. parT.Add(set[i]);
  31. num++;
  32. }
  33. }
  34. for (var i = 0; i < parS.Count; i++) {
  35. if (parT[i] != parS[i]) {
  36. return false;
  37. }
  38. }
  39. return true;
  40. }
  41. }






原文地址:https://www.cnblogs.com/xiejunzhao/p/bd6d51f34f6d8d1c43ad4abada327833.html