1094. The Largest Generation (25)

A family hierarchy is usually presented by a pedigree tree where all the nodes on the same level belong to the same generation. Your task is to find the generation with the largest population.

Input Specification:

Each input file contains one test case. Each case starts with two positive integers N (<100) which is the total number of family members in the tree (and hence assume that all the members are numbered from 01 to N), and M (<N) which is the number of family members who have children. Then M lines follow, each contains the information of a family member in the following format:

ID K ID[1] ID[2] ... ID[K]

where ID is a two-digit number representing a family member, K (>0) is the number of his/her children, followed by a sequence of two-digit ID's of his/her children. For the sake of simplicity, let us fix the root ID to be 01. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print in one line the largest population number and the level of the corresponding generation. It is assumed that such a generation is unique, and the root level is defined to be 1.

Sample Input:

23 13
21 1 23
01 4 03 02 04 05
03 3 06 07 08
06 2 12 13
13 1 21
08 2 15 16
02 2 09 10
11 2 19 20
17 1 22
05 1 11
07 1 14
09 1 17
10 1 18

Sample Output:

9 4

 1 #include<string>
 2 #include<iostream>
 3 #include<map>
 4 #include<stdio.h>
 5 #include<vector>
 6 using namespace std;
 7 
 8 struct node
 9 {
10     vector<int> child;
11 };
12 
13 node Tree[110];
14 int Level[110];
15 int MAX = -1;
16 void DFS(int n,int level)
17 {
18     if(MAX < level)
19         MAX = level;
20     ++Level[level];
21     for(int i = 0 ;i < Tree[n].child.size() ;++i)
22         DFS(Tree[n].child[i],level+1);
23 }
24 int main()
25 {
26     int n,m,tid,num,id;
27     scanf("%d%d",&n,&m);
28     for(int i = 0 ;i < m ;++i)
29     {
30         scanf("%d%d",&id,&num);
31         for(int k = 0;k < num;++k)
32         {
33             scanf("%d",&tid);
34             Tree[id].child.push_back(tid);
35         }
36     }
37     DFS(1,1);
38     int maxL = -1;
39     int index = -1;
40     for(int i = 1; i <= MAX;++i)
41     {
42         if(Level[i] > maxL)
43         {
44             maxL = Level[i];
45             index = i;
46         }
47     }
48     printf("%d %d
",maxL,index);
49     return 0;
50 }