Perfect Pth Powers zoj 2124 pku1730 hunnu10585

测试数据中有负数。

湖南师范大学（hunnu OJ)提交时要使用%I64d

只要将n进行素因子分解，把所有素因子数目的gcd求出来就行。注意：n可能是负数，所以对于负数还需要将求出来的结果试除2，直到结果不是偶数才是最后负数的结果

#include<stdio.h>
#include<string.h>
#include<math.h>
#define nmax 65536
int prime[nmax], plen, cfactor[nmax], clen;
void init() {
	memset(prime, -1, sizeof(prime));
	int i, j;
	for (i = 2, plen = 0; i < nmax; i++) {
		if (prime[i]) {
			for (j = i + i; j < nmax; j += i) {
				prime[j] = 0;
			}
		}
	}
	for (i = 2, plen = 0; i < nmax; i++) {
		if (prime[i]) {
			prime[plen++] = i;
		}
	}
}
int gcd(int n, int m) {
	int te;
	if (n < m) {
		te = n, n = m, m = te;
	}
	if (m == 0) {
		return n;
	}
	return gcd(m, n % m);
}
int solve(long long n) {
	int i, te, res, cnt;
	long long m;
	m = n > 0 ? n : -n;
	te = (int) (sqrt(m * 1.0));
	for (i = 0, clen = 0; (i < plen) && (prime[i] <= te); i++) {
		if (m % prime[i] == 0) {
			cnt = 0;
			while (m % prime[i] == 0) {
				m /= prime[i];
				cnt++;
			}
			cfactor[clen] = cnt;
			clen++;
		}
	}
	if (clen == 0) {
		return 1;
	}
	for (i = 1, res = cfactor[0]; i < clen; i++) {
		res = gcd(res, cfactor[i]);
	}
	return res;
}

int main() {
#ifndef ONLINE_JUDGE
	freopen("t.txt", "r", stdin);
#endif
	init();
	long long n;
	int res;
	while (scanf("%I64d", &n) != EOF && n) {
		res = solve(n);
		if (n < 0) {
			while (!(res & 1)) {
				res >>= 1;
			}
		}
		printf("%d\n", res);
	}
	return 0;
}