Lc102_二叉树的层序遍历

package com.example.demo;

import org.springframework.util.CollectionUtils;

import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
import java.util.Queue;

/**
 * 102. 二叉树的层序遍历
 * 给你一个二叉树,请你返回其按 层序遍历 得到的节点值。 (即逐层地,从左到右访问所有节点)。
 * <p>
 * <p>
 * <p>
 * 示例:
 * 二叉树:[3,9,20,null,null,15,7],
 * <p>
 * 3
 * / 
 * 9  20
 * /  
 * 15   7
 * 返回其层次遍历结果:
 * <p>
 * [
 * [3],
 * [9,20],
 * [15,7]
 * ]
 * 通过次数144,064提交次数229,041
 */
public class Lc102 {

    public static void main(String[] args) {
        Integer[] arr = new Integer[]{1, 2, 3, 4, 5, 6, 7};
        TreeNode root = CreateNode.createTree(arr).get(0);
        List<List<Integer>> lists = levelOrder(root);
        lists.forEach(n -> {
            n.forEach(m -> {
                System.out.print(m + ",");
            });
            System.out.println();
        });
    }

    public static List<List<Integer>> levelOrder(TreeNode root) {

        List<List<Integer>> res = new ArrayList<>();
        if (root == null) {
            return res;
        }
        Queue<TreeNode> queue = new LinkedList<>();
        TreeNode curr = root;
        queue.add(curr);
        while (!queue.isEmpty()) {
            List<Integer> list = new ArrayList<>();
            int size = queue.size();
            for (int i = 0; i < size; i++) {
                list.add(queue.peek().val);
                curr = queue.poll();
                if (curr.left != null) {
                    queue.add(curr.left);
                }
                if (curr.right != null) {
                    queue.add(curr.right);
                }
            }
            if (!CollectionUtils.isEmpty(list)) {
                res.add(list);
            }
        }
        return res;
    }
}

原文地址:https://www.cnblogs.com/xiaoshahai/p/13130392.html