每天一道LeetCode--118. Pascal's Triangle(杨辉三角)

Given numRows, generate the first numRows of Pascal's triangle.

For example, given numRows = 5,
Return

[
     [1],
    [1,1],
   [1,2,1],
  [1,3,3,1],
 [1,4,6,4,1]
]

solution:

ackage cn.magicdu;

import java.util.ArrayList;
import java.util.List;

public class _118_Pascal_Triangle {

    public List<List<Integer>> generate(int numRows) {
        if (numRows < 0) {
            return null;
        }
        List<List<Integer>> l1 = new ArrayList<>();
        if (numRows >= 1) {
            List<Integer> list = new ArrayList<>();
            list.add(1);
            l1.add(list);
        }
        if (numRows >= 2) {
            List<Integer> list = new ArrayList<>();
            list.add(1);
            list.add(1);
            l1.add(list);
        }
        if (numRows >= 3) {
            for (int i = 3; i <= numRows; i++) {
                List<Integer> list = new ArrayList<>();
                List<Integer> prev = l1.get(i - 2);
                list.add(1);
                for (int j = 2; j <= i - 1; j++) {
                    list.add(prev.get(j - 2) + prev.get(j - 1));
                }
                list.add(1);
                l1.add(list);
            }

        }

        return l1;
    }

}
原文地址:https://www.cnblogs.com/xiaoduc-org/p/6060897.html