十进制八进制转换

long change(long a)
{
    int my[MAX_SIZE];
    int i=0;
    long tmp=0;

    while (a)
    {
        my[i++]=a%8;
        a/=8;
    }
    int j=i;
    for (i=0;i<j;++i)
        tmp=tmp+my[i]*(long)pow(10.0,i);

    return tmp;
}
原文地址:https://www.cnblogs.com/xiaodi914/p/5843005.html