70.lambda表达式逻辑(二进制转换为为十进制)

#include <iostream>
#include <cstring>
using namespace std;

void main()
{
    auto fun = [](char *str)->int 
    {
        int res = 0;
        char *p = str;
        int length = strlen(str);
        for (int i = 0; i < length; i++)
        {
            res *= 2;
            res += str[i] - '0';
        }
        return res;
    };

    char str[100];
    cin >> str;
    cout << fun(str) << endl;
    system("pause");
}