oracle——笔记——简单查询语句

create table emp2 ( empno number(4),
                    ename varchar2(10),
                    job varchar2(9),
                    mgr number(4),
                    hiredate date,
                    sal number(7,2),
                    comm number(7,2),
                    deptno number(2) 
                 );
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insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7369, 'SMITH', 'CLERK', 7902, to_date('17-12-1980', 'dd-mm-yyyy'), 800.00, null, 20);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7499, 'ALLEN', 'SALESMAN', 7698, to_date('20-02-1981', 'dd-mm-yyyy'), 1600.00, 300.00, 30);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7521, 'WARD', 'SALESMAN', 7698, to_date('22-02-1981', 'dd-mm-yyyy'), 1250.00, 500.00, 30);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7566, 'JONES', 'MANAGER', 7839, to_date('02-04-1981', 'dd-mm-yyyy'), 2975.00, null, 20);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7654, 'MARTIN', 'SALESMAN', 7698, to_date('28-09-1981', 'dd-mm-yyyy'), 1250.00, 1400.00, 30);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7698, 'BLAKE', 'MANAGER', 7839, to_date('01-05-1981', 'dd-mm-yyyy'), 2850.00, null, 30);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7782, 'CLARK', 'MANAGER', 7839, to_date('09-06-1981', 'dd-mm-yyyy'), 2450.00, null, 10);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7788, 'SCOTT', 'ANALYST', 7566, to_date('19-04-1987', 'dd-mm-yyyy'), 3000.00, null, 20);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7839, 'KING', 'PRESIDENT', null, to_date('17-11-1981', 'dd-mm-yyyy'), 5000.00, null, 10);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7844, 'TURNER', 'SALESMAN', 7698, to_date('08-09-1981', 'dd-mm-yyyy'), 1500.00, 0.00, 30);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7876, 'ADAMS', 'CLERK', 7788, to_date('23-05-1987', 'dd-mm-yyyy'), 1100.00, null, 20);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7900, 'JAMES', 'CLERK', 7698, to_date('03-12-1981', 'dd-mm-yyyy'), 950.00, null, 30);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7902, 'FORD', 'ANALYST', 7566, to_date('03-12-1981', 'dd-mm-yyyy'), 3000.00, null, 20);

insert into emp2 (EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO)
values (7934, 'MILLER', 'CLERK', 7782, to_date('23-01-1982', 'dd-mm-yyyy'), 1300.00, null, 10);

=============================================================================================================================

create table dept2 ( deptno number(2),
                     dname varchar2(14),
                     loc varchar2(13)
                   );

----------------------------------------------------

insert into dept2 (DEPTNO, DNAME, LOC)
values (10, 'ACCOUNTING', 'NEW YORK');

insert into dept2 (DEPTNO, DNAME, LOC)
values (20, 'RESEARCH', 'DALLAS');

insert into dept2 (DEPTNO, DNAME, LOC)
values (30, 'SALES', 'CHICAGO');

insert into dept2 (DEPTNO, DNAME, LOC)
values (40, 'OPERATIONS', 'BOSTON');

============================================================

create table salgrade2 ( grade number,
                         losal number,
                         hisal number
                       );

--------------------------------------------------

insert into salgrade2 (GRADE, LOSAL, HISAL)
values (1, 700, 1200);

insert into salgrade2 (GRADE, LOSAL, HISAL)
values (2, 1201, 1400);

insert into salgrade2 (GRADE, LOSAL, HISAL)
values (3, 1401, 2000);

insert into salgrade2 (GRADE, LOSAL, HISAL)
values (4, 2001, 3000);

insert into salgrade2 (GRADE, LOSAL, HISAL)
values (5, 3001, 9999);


========================================================

select * from emp2;

select * from dept2;

select * from salgrade2;

=====================================
select * from emp2;        --employee2 员工表
select * from dept2;       --department2 部门表
select * from salgrade2;   -- salary grade2 工资等级表

-----------------------------------------------------
emp2

empno    员工编号
ename    员工姓名
job      工作/工种
mgr      manager上级编号
hiredate 入职日期
sal      salary 工资
comm     奖金/津贴
deptno   部门编号
---------------------

dept2

deptno  部门号
dname   部门名称
loc     所在地
---------------------------
salgrade2

grade                   等级
losal lowest salary     最低工资
hisal high salary       最高工资

=============================================


数据查询语句:
select from where





查询emp2表中,所有员工的姓名、工资、部门号:
select ename,sal,deptno from emp2;




查询emp2表中,工资大于1500 的员工信息:
select * from emp2 where sal > 1500;





查询emp2表中,上级是7698 的员工姓名和津贴:
select ename,comm from emp2 where mgr = 7698;





列的别名:
select ename,sal,deptno from emp2; select ename 姓名,sal 工资,deptno 部门号 from emp2; select ename as 姓名,sal as 工资,deptno as 部门号 from emp2; select ename as e,sal as s,deptno as d from emp2; select ename as "Esc",sal as "alS",deptno as "dDD" from emp2; select ename as "e%",sal as "s#",deptno as "d()" from emp2;



==============================================================================================================

算术运算
+ - * / () 支持数值型和日期型(只能加减)数据:




查询每个员工的年薪:
select ename,sal,sal*12 from emp2;




给20部门员工,涨薪300之后,工资是多少?:
select ename,sal,sal+300 from emp2 where deptno = 20;





查询每名员工的 工资奖金和 :
select sal,comm,sal+comm from emp2;





运算中如果有空值,那么最后结果为空
--空值替换 nvl() select sal,comm,nvl(comm,0),sal+nvl(comm,0) from emp2; select * from emp2; insert into emp2(empno) values(1122); delete from emp2 where empno = 1122; select ename,nvl(ename,'未知') from emp2;







连接符 :
select ename,sal from emp2; select ename||'的工资是'||sal||',部门是'||deptno from emp2;





去重


查询emp中,有多少个部门:
select distinct deptno from emp2;




查询emp中,有多少种工作
select distinct job from emp2;







where 比较运算符 一般的比较运算符 > >= <= < = != <> 特殊的比较运算符 between……and…… in(……) like …… 像 模糊查询 is null 空值




select * from emp2 where comm is null;


select * from emp2 where comm is not null;







查询工资在1500 到
3000 的员工信息: select * from emp2 where sal between 1500 and 3000; --闭区间 下限 上限
select * from emp2 where sal >= 1500 and sal <= 3000;




查询从事CLERK或SALESMAN 的员工信息:
1)字符串 2)关于大小写 select * from emp2 where job in('CLERK','SALESMAN'); select * from emp2 where job = 'CLERK' or job = 'SALESMAN' ; select * from emp2 where sal in(1500,3000); select * from emp2 where sal = 1500 or sal = 3000;







like select * from emp2 where ename like 'S%';





% sql里的% 等同于linux的* ,代表零个或多个任意字符 _ 代表一个任意字符 select * from emp2 where ename like 'S_ITH'; select t.*,t.rowid from emp2 t; select emp2.*,rowid from emp2;


查询以S
%开头的员工信息: select * from emp2 where ename like 'S\%%' escape '\'; escape '\':定义\这个符号后面符号位普通字符串,不是系统里默认的符号。即转义 select * from emp2 where ename like 'S|%%' escape '|'; select * from emp2 where ename like 'S%\%' escape '\';

escape: 用来转译的,比如数据库中有个表 test字段name 中存了字符'%',那么我查询的时候如果想查询第二位是 '%'的记录就要用到模糊查询,

但是
'%'是模糊查询的通配符,我不能如下查询: select * from test where name like '_%%';


这样系统不会把第二个【
%】当做字符,只能转译,转译默认的符号是 【\】 select * from test where name like '_\%%';


但是可以自定义转义符,这时候就用
escape,比如定义【*】为转义符 select * from test where name like '_*%%' escape '*';




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逻辑运算符 and or not () 运算优先级:not > and > or ,()优先级最高


查询,
20 部门中,从事CLERK 工作的员工: select * from emp2 where deptno = 20 and job = 'CLERK';


查询,
30 部门中,奖金为空的员工信息: select * from emp2 where deptno = 30 and comm is null;


查询,除10 部门之外,工资大于1500 的员工信息:
select * from emp2 where deptno != 10 and sal > 1500;


查询,工作是SALESMAN ,或工资不小于3000 的员工:
select * from emp2 where job = 'SALESMAN' or sal >= 3000;

查询,工作不是SALESMAN ,也不是CLERK 的员工:
select * from emp2 where job != 'SALESMAN' and job != 'CLERK'; select * from emp2 where job in('SALESMAN','CLERK'); select * from emp2 where job not in('SALESMAN','CLERK');


查询,工作是SALESMAN,或,工作是PRESIDENT并且工资大于1500的员工信息:
select * from emp2 where job = 'SALESMAN' or job = 'PRESIDENT' and sal > 1500;



查询,工作是SALESMAN或PRESIDNET,并且工资大于1500 的员工信息:
select * from emp2 where (job = 'SALESMAN' or job = 'PRESIDENT') and sal > 1500; select * from emp2 where job in('SALESMAN','PRESIDENT') and sal > 1500;








order by 排序 select from where order by 列名|别名|算术表达式|函数 order by 列1,别名,函数 order by 列1,列2 desc; order by的位置:在整个查询语句的最后多次排序





select * from emp2 order by sal; --升序 select * from emp2 order by sal asc; --升序 select * from emp2 order by sal desc; --降序 select ename 姓名,job 工作 from emp2 where deptno = 20 order by 姓名 desc;



查询员工信息,结果按照工资奖金和 升序排序:
select emp2.*,sal+nvl(comm,0) from emp2 order by sal+nvl(comm,0);


查询员工信息,结果按照部门号排序;如果部门号相同,按照工资降序排序
select * from emp2 order by deptno asc,sal desc;



函数 单组函数 一个值对应一个结果 分组函数
/聚合函数 多个值对应一个结果 avg() sum() 单组函数 --字符函数 UPPER() LOWER() INITCAP() ---字母大小写 大写 小写 首字母大写 replace() substr() concat() nvl() nvl2() 替换 截取 连接


select ename,lower(ename),initcap(ename) from emp2; select t.*,t.rowid from emp2 t; select * from emp2 where lower(job) = 'clerk'; select ename,replace(ename,'S','s') from emp2; select ename,substr(ename,2,3) from emp2; 起始位,长度


查询工作名称以SALES 开头的员工信息:
select * from emp2 where job like 'SALES%'; select * from emp2 where substr(job,1,5) = 'SALES'; select ename||'的工资是'||sal||deptno from emp2; select concat(ename,sal) from emp2; select concat(concat(ename,'的工资是'),sal) from emp2;





函数是可以嵌套的
select substr(concat(ename,'的工资是'),5,5) from emp2; select comm,nvl(comm,0),nvl2(comm,1000,0) from emp2; 非空替换,空值替换






数值函数
round(x[,y]) 取整或保留指定小数位,规则:四舍五入 trunc(x[,y]) 取整或保留指定小数位,规则:截断 mod(x,y) 取模/取余 round(5.72) = 6 round(5.718,2) = 5.72 round(04.718,-1) = 0 trunc(5.72) = 5 trunc(5.718,2) = 5.71 trunc(05.718,-1) = 0 select round(5.72), round(5.718,2),round(5.718,-1) from dual; select trunc(5.718,2),mod(8,4),mod(10,3) from dual;

dual表 作用:语句补全
select * from dual; select sysdate from dual; select 12*15,round(1000/23,2) from dual; select Sys_Context('userenv','db_name') from dual;--查看当前数据库 名 select Dbms_Random.random from dual;--获得一个随机数 select Dbms_Random.value(10,20) from dual;--获得一个随机数











日期函数 使用insert,新增一条记录: 员工编号:
1122 员工工作:SALESMAN 入职日期:2018年7月1号 insert into 表名(列名) values(列对应的值); insert into emp(empno,job,hiredate) values(1122,'SALESMAN','01-7月-18'); insert into emp(empno,job,hiredate) values(1122,'SALESMAN','2018-7-1'); select * from emp; --1)默认日期格式 select * from nls_session_parameters; alter session set NLS_DATE_FORMAT='YYYY-MM-DD'; alter session set NLS_DATE_FORMAT='DD-MON-RR'; --2) 日期函数 to_date(日期,格式) insert into emp(empno,job,hiredate) values(1123,'SALESMAN',to_date('10-1-2018','MM-DD-YYYY')); --查询入职日期早于1981年9 月30 号的员工信息 select from where hiredate < to_date()
原文地址:https://www.cnblogs.com/xiaobaibailongma/p/12258070.html