ES6 Set 常用

Set 对象作用

数组去重,注意4 ‘4’ 不同

let arr = [1, 2, 3, 4, 4, '4', '4'];
let mySet = new Set(arr);
[...mySet]; // [1, 2, 3, 4, '4']

并集

let a = new Set([1, 2, 3]);
let b = new Set([4, 3, 2]); 
let union = new Set([...a, ...b]); // {1, 2, 3, 4}
[...union] // [1,2,3,4]

交集

let a = new Set([1, 2, 3]); 
let b = new Set([4, 3, 2]); 
let intersect = new Set([...a].filter(x => b.has(x))); // {2, 3}
[...intersect] // [2,3]

差集

let a = new Set([1, 2, 3]); 
let b = new Set([4, 3, 2]); 
let difference = new Set([...a].filter(x => !b.has(x))); // {1}
[...difference] // [1]

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原文地址:https://www.cnblogs.com/xiangsj/p/14032308.html