将url获取到的参数解码

通过decodeURL()解码

  var url = location.search; //获取url中"?"符后的字串
    if (url.indexOf("?") != -1) {   
        var str = url.substr(1) //从第一个字符开始 因为第0个是?号 获取所有除问号的所有符串
        strs = str.split("&")  
        var obj = {}
        for(var i = 0; i < strs.length; i++){
            var str1 = strs[i].split('=')
            obj[str1[0]] = str1[1]
            var newarr = []
            newarr.push(obj)
        } 
        var id = newarr[0].id         //获取到id
        var cityname = decodeURI(newarr[0].cityname)
    }

  

原文地址:https://www.cnblogs.com/xhrr/p/11286840.html