javascript获取url中的参数值

javascript的实现代码如下:

    function QueryString(fieldName)
    { 
      var urlString = document.location.search;
      if(urlString !=null)
      {
           var typeQu = fieldName+"=";
           var urlEnd = urlString.indexOf(typeQu);
           if(urlEnd !=-1)
           {
                var paramsUrl = urlString.substring(urlEnd+typeQu.length);
                var isEnd =  paramsUrl.indexOf('&');
                if(isEnd !=-1)
                {
                     return paramsUrl.substring(0, isEnd);
                }
                else
                {
                    return paramsUrl;
                }
           }
           else
           {
                return null;
           }
      }
     else
     {
        return null;
     }
    }
原文地址:https://www.cnblogs.com/x00479/p/3238764.html