62. Unique Paths

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).

The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).

How many possible unique paths are there?

Above is a 3 x 7 grid. How many possible unique paths are there?

Note: m and n will be at most 100.

题目:机器人从左上角到右下角,每次只能往右或者下走一格,问有多少种走法?

思路:DP问题,构造一个m*n矩阵,用step[row][col]代表走到(i,j)节点的多种线路数,因为只能往右或者下移动,所以矩阵的第一行(只能往右移动)和第一列(只能往下移动)为1.其它节点的线路数为

 steps[i][j] = steps[i - 1][j] + steps[i][j - 1];
 1     public int uniquePaths(int m, int n) {
 2          if (m == 0 || n == 0) return 0;
 3          if (m == 1 || n == 1) return 1;
 4          int[][] steps = new int[m][n];
 5          for (int i = 0; i < m; i++)
 6              for (int j = 0; j < n; j++) {
 7                  if (i==0 || j==0)  steps[i][j] = 1;
 8                  else steps[i][j] = steps[i - 1][j] + steps[i][j - 1];
 9              }
10          return steps[m - 1][n - 1];
11     }
 
原文地址:https://www.cnblogs.com/wzj4858/p/7675910.html