camelcase-hankerrank

int camelcase(string s) {
int cnt=0;
int a;
for(int i=0;i<s.size();i++)
{
a=s[i];
if(65<=a&&a<=90)
{
cnt++;
 
}
}
cnt++;
return cnt;

}
原文地址:https://www.cnblogs.com/wzhtql/p/10539887.html