反转链表

题目:

输入一个链表,反转链表后,输出新链表的表头

解答:

 1 public class Solution {
 2 
 3     public static ListNode reverseList(ListNode pHead) {
 4         if(pHead == null) {
 5             return null;
 6         }
 7 
 8         ListNode pReversedHead = null;
 9 
10         ListNode pPrev = null;
11         ListNode pCurrent = pHead;
12         ListNode pNext = null;
13 
14         while(current != null) {
15             pNext = pCurrent.next;
16 
17             if(pNext == null) {
18                 pReversedHead = pCurrent;
19             }
20 
21             pCurrent.next = pPrev;
22 
23             pPrev = pCurrent;
24             pCurrent = pNext;
25         }
26 
27         return pReversedHead;
28     }
29 }

原文地址:https://www.cnblogs.com/wylwyl/p/10465839.html