显示表达式的运算形式
1、显示表达式1*2+3*4+...+9*10的运算表示形式
源程序代码如下：
/*
2017年6月7日22:54:51
功能：实现1*2+3*4+...+9*10表达式的操作
*/
#include "stdio.h"
#include "string.h"
char a[100];
int i, j = 0;
int main()
{
for(i = 1; i <= 10; i++)
{
if(i % 2 != 0)
{
a[j++] = i +'0';
a[j++] = '*';
}
else if(i % 2 == 0 && i != 10)
{
a[j++] = i +'0';
a[j++] = '+';
}
else
{
a[j++] = 1 + '0';
a[j++] = '0';
}
}
a[j] = ' ';
puts(a);
return 0;
}
/*
总结：
在VC++6.0中显示的结果：
——————————————————
1*2+3*4+5*6+7*8+9*10
——————————————————
*/
2、显示表达式1*2+3*4+...+99*100的运算表示形式
源程序代码如下：
/*
2017年6月7日22:44:12
功能：显示表达式1*2+3*4+...+99*100的表示形式
*/
#include"stdio.h"
#include"string.h"
int main()
{
char seq[10000] = "alex";
int i, j = 0, first, second;
for (i = 1; i <= 100; i++)
{
if (i < 10)
if (i % 2 != 0)
seq[j++] = '0' + i,seq[j++] = '*';
else
seq[j++] = '0' + i,seq[j++] = '+';
else if (i >= 10 && i <= 99)
{
first = i % 10;
second = (i - first) / 10;
if (i % 2 != 0)
seq[j++] = '0' + second,seq[j++] = '0' + first,seq[j++] = '*';
else
seq[j++] = '0' + second,seq[j++] = '0' + first,seq[j++] = '+';
}
else if (i == 100)
seq[j++] = '0' + 1,seq[j++] = '0',seq[j] = '0';
}
puts(seq);
return 0;
}
/*
总结：
在VC++6.0中显示的结果:
——————————————————————————————————
1*2+3*4+5*6+7*8+9*10+11*12+13*14+15*16+17*18+19*20+21*22+23*24+25*26
+27*28+29*30+31*32+33*34+35*36+37*38+39*40+41*42+43*44+45*46+47*48+
49*50+51*52+53*54+55*56+57*58+59*60+61*62+63*64+65*66+67*68+69*70+
71*72+73*74+75*76+77*78+79*80+81*82+83*84+85*86+87*88+89*90+91*92+
93*94+95*96+97*98+99*100
——————————————————————————————————
*/
3、显示表达式1*2+3*4+...+99*100的运算表示形式（采取交互的形式）
程序源代码如下：
/*
2017年6月8日08:03:38
功能：采取交互的形式输出以下的表达式
*/
#include "stdio.h"
#include "string.h"
int main()
{
char seq[1000];
int i, j = 0, first, second, num;
printf("please input a odd number: ");
scanf("%d",&num);
if(num <= 10)
{
for (i = 1; i <= num; i++)
{
if (i % 2 != 0)
seq[j++] = '0' + i,seq[j++] = '*';
else if(i % 2 == 0 && i != num)
seq[j++] = '0' + i,seq[j++] = '+';
else if (i == num)
seq[j++] = '0' + 1,seq[j++] = '0';
}
}
else if(num > 10 && num < 100)
{
for (i = 1; i <= num; i++)
{
if (i < 10)
if (i % 2 != 0)
seq[j++] = '0' + i,seq[j++] = '*';
else
seq[j++] = '0' + i,seq[j++] = '+';
else if (i >= 10 && i < num)
{
first = i % 10;
second = (i - first) / 10;
if (i % 2 != 0)
seq[j++] = '0' + second,seq[j++] = '0' + first,seq[j++] = '*';
else if (i % 2 == 0 && i != num)
seq[j++] = '0' + second,seq[j++] = '0' + first,seq[j++] = '+';
}
else if (i == num)
seq[j++] = '0' + second ,seq[j++] = '0' + (first + 1) ;
}
}
else if(num == 100)
{
for (i = 1; i <= 100; i++)
{
if (i < 10)
if (i % 2 != 0)
seq[j++] = '0' + i,seq[j++] = '*';
else
seq[j++] = '0' + i,seq[j++] = '+';
else if (i >= 10 && i < 100)
{
first = i % 10;
second = (i - first) / 10;
if (i % 2 != 0)
seq[j++] = '0' + second,seq[j++] = '0' + first,seq[j++] = '*';
else
seq[j++] = '0' + second,seq[j++] = '0' + first,seq[j++] = '+';
}
else if (i == 100)
seq[j++] = '0' + 1,seq[j++] = '0',seq[j++] = '0';
}
}
seq[j] = ' ';
puts(seq);
}
/*
总结：
在VC++6.0中显示的结果：
-----------------------------------------------------------------
please input a odd number: 98
1*2+3*4+5*6+7*8+9*10+11*12+13*14+15*16+17*18+19*20+21*22+23*24+25*26+27*28+29*30
+31*32+33*34+35*36+37*38+39*40+41*42+43*44+45*46+47*48+49*50+51*52+53*54+55*56+5
7*58+59*60+61*62+63*64+65*66+67*68+69*70+71*72+73*74+75*76+77*78+79*80+81*82+83*
84+85*86+87*88+89*90+91*92+93*94+95*96+97*98
please input a odd number: 100
1*2+3*4+5*6+7*8+9*10+11*12+13*14+15*16+17*18+19*20+21*22+23*24+25*26+27*28+29*30
+31*32+33*34+35*36+37*38+39*40+41*42+43*44+45*46+47*48+49*50+51*52+53*54+55*56+5
7*58+59*60+61*62+63*64+65*66+67*68+69*70+71*72+73*74+75*76+77*78+79*80+81*82+83*
84+85*86+87*88+89*90+91*92+93*94+95*96+97*98+99*100
-----------------------------------------------------------------
注意：将整数型数据转化成字符型数据的格式
char m;
int n;
m = n + '0';（像10、100之类的数据除外）
*/