LeetCode-485. Max Consecutive Ones

Given a binary array, find the maximum number of consecutive 1s in this array.

Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

public class Solution {
    public int findMaxConsecutiveOnes(int[] nums) {
        if (nums == null)
            return 0;
        int sum = 0, b = 0;
        for (int v : nums) {
            b += v;
            if (v == 0)
                b = 0;
            if (sum < b)
                sum = b;
        }
        return sum;
    }
}