数学概念——G 最大公约数

G - 数论，最大公约数

Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u

Submit Status

Description

There is a hill with n holes around. The holes are signed from 0 to n-1. 



A rabbit must hide in one of the holes. A wolf searches the rabbit in anticlockwise order. The first hole he get into is the one signed with 0. Then he will get into the hole every m holes. For example, m=2 and n=6, the wolf will get into the holes which are signed 0,2,4,0. If the rabbit hides in the hole which signed 1,3 or 5, she will survive. So we call these holes the safe holes. 

 

Input

The input starts with a positive integer P which indicates the number of test cases. Then on the following P lines,each line consists 2 positive integer m and n(0<m,n<2147483648). 

 

Output

For each input m n, if safe holes exist, you should output "YES", else output "NO" in a single line. 

 

Sample Input

2

1 2

2 2

 

Sample Output

NO

YES

解题思路：这个题目的意思就是判断输入的这两个数的最大公约数是否为1

程序代码：

#include <cstdio>
using namespace std;
long long hcf(long long  a,long long  b)
      {
          if(b==0)
            return a;
          else
            return hcf(b,a%b);
      }
int main()
{
    int t;
    long long  m,n;
    scanf("%d",&t);
    while(t--)
    {
        scanf("%d%d",&m,&n);
        if(hcf(m,n)==1)
             printf("NO
");
      else
             printf("YES
");
    }
    return 0;
}