Django urls.py报错: raise TypeError('view must be a callable or a list/tuple in the case of include()

问题重现:

C:Userswuzhi_000DesktopPythonmyweb>python manage.py runserver
Performing system checks...

Unhandled exception in thread started by <function wrapper at 0x0000000004B6F128>
Traceback (most recent call last):
  File "C:Python27libsite-packagesdjangoutilsautoreload.py", line 226, in wrapper
    fn(*args, **kwargs)
  File "C:Python27libsite-packagesdjangocoremanagementcommands
unserver.py", line 121, in inner_run
    self.check(display_num_errors=True)
  File "C:Python27libsite-packagesdjangocoremanagementase.py", line 385, in check
    include_deployment_checks=include_deployment_checks,
  File "C:Python27libsite-packagesdjangocoremanagementase.py", line 372, in _run_checks
    return checks.run_checks(**kwargs)
  File "C:Python27libsite-packagesdjangocorechecks
egistry.py", line 81, in run_checks
    new_errors = check(app_configs=app_configs)
  File "C:Python27libsite-packagesdjangocorechecksurls.py", line 14, in check_url_config
    return check_resolver(resolver)
  File "C:Python27libsite-packagesdjangocorechecksurls.py", line 24, in check_resolver
    for pattern in resolver.url_patterns:
  File "C:Python27libsite-packagesdjangoutilsfunctional.py", line 35, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "C:Python27libsite-packagesdjangourls
esolvers.py", line 310, in url_patterns
    patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
  File "C:Python27libsite-packagesdjangoutilsfunctional.py", line 35, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "C:Python27libsite-packagesdjangourls
esolvers.py", line 303, in urlconf_module
    return import_module(self.urlconf_name)
  File "C:Python27libimportlib\__init__.py", line 37, in import_module
    __import__(name)
  File "C:Userswuzhi_000DesktopPythonmywebmyweburls.py", line 22, in <module>
    url(r'^index/$', 'blog.views.index'),
  File "C:Python27libsite-packagesdjangoconfurls\__init__.py", line 85, in url
    raise TypeError('view must be a callable or a list/tuple in the case of include().')
TypeError: view must be a callable or a list/tuple in the case of include().

解决方案:

Django doc:

The `urlpatterns` list routes URLs to views. For more information please see:
    https://docs.djangoproject.com/en/1.10/topics/http/urls/
Examples:
Function views
    1. Add an import:  from my_app import views
    2. Add a URL to urlpatterns:  url(r'^$', views.home, name='home')
Class-based views
    1. Add an import:  from other_app.views import Home
    2. Add a URL to urlpatterns:  url(r'^$', Home.as_view(), name='home')
Including another URLconf
    1. Import the include() function: from django.conf.urls import url, include
    2. Add a URL to urlpatterns:  url(r'^blog/', include('blog.urls'))

import app.views import view_name

url(

url(r'^index/$', view_name, name='view_name'),

)

原文地址:https://www.cnblogs.com/wuzhiyi/p/6495033.html