indexOf返回值问题

  

String s  = "aoood";
System.out.println(s.indexOf(""));//返回0 System.out.println(s.indexOf("w"));//返回-1 例如 var customerKinds="GR,QY"; (customerKinds.indexOf(customerKind)!= -1){ -------------------------------------------------------------- } customerKind="''" 则会全部显示 customerKind有值,则会根据值显示

  

原文地址:https://www.cnblogs.com/wuxu/p/10694072.html