南京理工 ACM

链接  http://icpc.njust.edu.cn/Contest/194/Problem/C

#include<iostream>
#include<stdio.h>
#include<algorithm>
#include<cstring>
#include<cmath>
using namespace std;

long long pow( int num )
{
    long long res = 1;
    for( int i = 1; i <= num; i++ )
    res *= 2;
    return res;
}
long long max( long long a,long long b ){return a>b?a:b;}
int main( )
{
    long long a,b,c,d,num1,num2;
    long long dp[70];
    while( scanf("%lld%lld",&a,&b) != EOF )
    {
        a; b++;
        memset( dp,0,sizeof(dp) ); long long res = 0;
        for( int i = 1; i <= 63; i++ )
        {
             c = a%pow(i);
             num1 = (a-c)/2 + max( (c-pow(i-1)),0 );
             d = b%pow(i);
             num2 = (b-d)/2 + max( (d-pow(i-1)),0 );
            dp[i] = ( dp[i-1] + num2 - num1 )/2;
            res  += dp[i];
        }
        printf("%lld\n",res);
    }
    return 0;
}

  

原文地址:https://www.cnblogs.com/wulangzhou/p/3086792.html