605. Can Place Flowers(LeetCode)

Suppose you have a long flowerbed in which some of the plots are planted and some are not. However, flowers cannot be planted in adjacent plots - they would compete for water and both would die.

Given a flowerbed (represented as an array containing 0 and 1, where 0 means empty and 1 means not empty), and a number n, return if n new flowers can be planted in it without violating the no-adjacent-flowers rule.

Example 1:

Input: flowerbed = [1,0,0,0,1], n = 1
Output: True

Example 2:

Input: flowerbed = [1,0,0,0,1], n = 2
Output: False

Note:

  1. The input array won't violate no-adjacent-flowers rule.
  2. The input array size is in the range of [1, 20000].
  3. n is a non-negative integer which won't exceed the input array size.
     1     class Solution {
     2     public:
     3         bool canPlaceFlowers(vector<int>& flowerbed, int n) {
     4         int count = 0;
     5         int len = flowerbed.size();
     6         vector<int> vet(len+2, 0);
     7         for (int i = 0; i < len; i++)
     8         {
     9             vet[i+1]=(flowerbed[i]);
    10         }
    11         for (int i = 0; i < len; i++)
    12         {
    13             if (vet[i] == 0 && vet[i + 1] == 0 && vet[i + 2] == 0)
    14             {
    15                 count++;
    16                 vet[i+1]=1;
    17             }
    18         }
    19         //cout <<count<< endl;
    20         if (n <= count)
    21             return true;
    22         else
    23             return false;
    24         }
    25     };
原文地址:https://www.cnblogs.com/wujufengyun/p/7197310.html