349. Intersection of Two Arrays(LeetCode)

Given two arrays, write a function to compute their intersection.

Example:
Given nums1 = [1, 2, 2, 1]nums2 = [2, 2], return [2].

Note:

    • Each element in the result must be unique.
    • The result can be in any order.
       1 class Solution {
       2 public:
       3     vector<int> intersection(vector<int>& nums1, vector<int>& nums2) {
       4         set<int> s;
       5         vector<int>::iterator ite;
       6         ite = nums2.begin();
       7         for (int i = 0; i < nums2.size(); i++)
       8         {
       9             ite = find(nums1.begin(), nums1.end(), nums2[i]);
      10             if (ite != nums1.end())
      11             {
      12                 s.insert(*ite);
      13 
      14             }
      15         }
      16         vector<int> vet;
      17         set<int>::iterator ite1;
      18         for (ite1 = s.begin(); ite1 != s.end(); ite1++)
      19         {
      20             vet.push_back(*ite1);
      21         }
      22         return vet;
      23     }
      24 };
原文地址:https://www.cnblogs.com/wujufengyun/p/6795807.html