多线程之Semaphore登录限流示例

public static void main(String[] args) {

        //允许最大的登录数
        int slots=10;
        ExecutorService executorService = Executors.newFixedThreadPool(slots);
        LoginQueueUsingSemaphore loginQueue = new LoginQueueUsingSemaphore(slots);
        //线程池模拟登录
        for (int i = 1; i <= slots; i++) {
            final int num=i;
            executorService.execute(()->{
                 if (loginQueue.tryLogin()){
                     System.out.println("用户:"+num+"登录成功!");
                 }else {
                     System.out.println("用户:"+num+"登录失败!");
                 }
            });
        }
        executorService.shutdown();


        System.out.println("当前可用许可证数:"+loginQueue.availableSlots());

        //此时已经登录了10个用户,再次登录的时候会返回false
        if (loginQueue.tryLogin()){
            System.out.println("登录成功!");
        }else {
            System.out.println("系统登录用户已满,登录失败!");
        }
        //有用户退出登录
        loginQueue.logout();

        //再次登录
        if (loginQueue.tryLogin()){
            System.out.println("登录成功!");
        }else {
            System.out.println("系统登录用户已满,登录失败!");
        }

    }
class LoginQueueUsingSemaphore{

    private Semaphore semaphore;

    /**
     *
     * @param slotLimit
     */
    public LoginQueueUsingSemaphore(int slotLimit){
        semaphore=new Semaphore(slotLimit);
    }

    boolean tryLogin() {
        //获取一个凭证
        return semaphore.tryAcquire();
    }

    void logout() {
        semaphore.release();
    }

    int availableSlots() {
        return semaphore.availablePermits();
    }
}

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原文地址:https://www.cnblogs.com/wujf/p/15541172.html