jquery获取属性与属性值

1  var layIds = $("[lay-id]");
2         $.each(layIds, function (index, value, array) {
3             var id = $(value).attr("lay-id");
4             element.tabDelete('tab', id);
5         });
原文地址:https://www.cnblogs.com/wuhailong/p/7383836.html