数论:Zeller公式

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//Zeller公式
/*
输入一个日期,计算这天是星期几
*/
#include <bits/stdc++.h>
using namespace std;

int getId(int y, int m, int d) {
	if (m < 3) {y --; m += 12;}
	return 365 * y + y / 4 - y / 100 + y / 400 + (153 * (m - 3) + 2) / 5 + d - 307;
}
vector<int> date(int id) {
	int x = id + 1789995, n, i, j, y, m, d;
	n = 4 * x / 146097;
	x -= (146097 * n + 3) / 4;
	i = (4000 * (x + 1)) / 1461001; x -= 1461 * i / 4 - 31;
	j = 80 * x / 2447; d = x - 2447 * j / 80; x = j / 11;
	m = j + 2 - 12 * x; y = 100 * (n - 49) + i + x;
	return vector<int>({y, m, d});
}


void work() {
	int M, y, m, d;
	scanf("%d%d%d%d", &M, &y, &m, &d);
	int id = getId(y, m, d);
	int l = 0, r = sqrt(2e9);
	while (l < r) {
		int mid = (l + r) / 2;
		int v = M + (0 + mid) * (mid + 1) / 2;
		if (v >= 1000000000) r = mid;
		else l = mid + 1;
	}
	id += l;
	auto ret = date(id);
	printf("%d %d %d
", ret[0], ret[1], ret[2]);
}

int main() {
	int T;
	scanf("%d", &T);
	while (T--) work();
}

你将不再是道具,而是成为人如其名的人
原文地址:https://www.cnblogs.com/wsl-lld/p/13393561.html