第四次作业

1.1

#include <stdio.h>
int main(){
    int i,sum=0;
    i = 1;
    while(i <= 100)
    {
        sum += i;
        i++;
    }
    printf("sum = %d
",sum);
    return 0;
}

1.2

#include <stdio.h>
int main(){
    int i,sum = 0;
    i = 1;
    sum = 0;
    do{
        sum+=i;
        i++;
    }while(i <= 100);
    printf("sum = %d
",sum);
    return 0;

1.3

#include <stdio.h>
int main(){
    int i,sum=0;
    sum=0;
    for(i = 1;i <= 100;i++)
        sum += i;
    printf("sum = %d
",sum);
    return 0;
}

 

2.1

#include <stdio.h>
int main(){
    int i,sum = 1,n;
    i=1;
    printf("请输入n的值:");
    scanf("%d",&n);
    while(i <= n)
    {
        sum = sum*i;
        i++;
    }
    printf("sum = %d
",sum);
    return 0;
}

2.2

#include <stdio.h>
int main(){
    int i,sum = 1,n;
    i=1;
    printf("请输入n的值:");
    scanf("%d",&n);
    do{
        sum = sum*i;
        i++;
    }while(i <= n);
    printf("sum = %d
",sum);
    return 0;
}


2.3

#include <stdio.h>
int main(){
    int i,sum = 1,n;
    printf("请输入n的值:");
    scanf("%d",&n);
    for(i = 1;i <= n;i++)
    sum=sum*i;
    printf("sum = %d
",sum);
    return 0;
}

 


#include <stdio.h>
#include <math.h>
int main(){
    long int k,sum=1,sum1,sum2;
    do{
        sum+=k;
        k++;
    }while(k <= 100);
    for(k = 1;k< = 50;k++)
        sum1=k*k;
    for(k =1/k;  
    printf("总数为:%d
",sum+sum1+sum2);
    return 0;
}

#include <stdio.h>
int main(){
    char c;
    int zm = 0,sz = 0,kg = 0,qt = 0;
    while((c=getchar())!='
'){
        if((c>='a' && c<='z') ||(c>='A' && c<='Z'))
            zm++;
        if(c==' ')
            kg++;
        if(c>='0' &&c<='9')
            sz++;
        else
            qt++;
    }
    printf("字母个数:%d
",zm);
    printf("空格个数:%d
",kg);
    printf("数字个数:%d
",sz);
    printf("其他字符个数:%d
",qt);
}

 

#include<stdio.h>
int main(){
    int a,b,m,n;
    printf("请输入正整数m和n:
");
    scanf("%d%d",&a,&b);
    m=a;
    n=b;
    while(a!=b)
        if(a>b)
            a=a-b;
        else
            b=b-a;
    printf("最大公约数为:%d
",a);
    printf("最小公倍数为:%d
",m*n/a);
}

原文地址:https://www.cnblogs.com/ws562304130/p/5955784.html