json 解析

纠结了两天的json数组反序列化,终于在同事的帮助下,找到方法了,特作笔记如下:

using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
using System.Text; 

       string jsonText = "[{'a':'aaa','b':'bbb','c':'ccc'},{'a':'aaa2','b':'bbb2','c':'ccc2'}]";
        JArray ja = (JArray)JsonConvert.DeserializeObject(ReceivePlaceString);
       // JObject o = (JObject)ja[1];
      //  Response.Write(o["a"]);
        Response.Write(ja[0]["a"]);  

  

原文地址:https://www.cnblogs.com/wqing/p/3620539.html