【SDOI2008】仪仗队

//裸的欧拉函数
//y=kx
//求不同的k有多少
#include<bits/stdc++.h> #define ll long long #define N 40010 using namespace std; ll f[N],n,ans; inline ll read(){ char ch; bool f=false; ll res=0; while (((ch=getchar())<'0'||ch>'9')&&ch!='-'); if (ch=='-') f=true; else res=ch-'0'; while ((ch=getchar())>='0'&&ch<='9') res=(res<<3)+(res<<1)+ch-'0'; return f?~res+1:res; } int main(){ n=read(); if (n==1){ printf("0 "); return 0; } for (int i=1;i<=n;i++) f[i]=i; for (int i=2;i<=n;i++) if (f[i]==i) for (int j=i;j<=n;j+=i) f[j]=f[j]/i*(i-1); ans=2; for(int i=2;i<n;++i) ans+=f[i]*2; printf("%lld ",ans+1); return 0; }
原文地址:https://www.cnblogs.com/wjnclln/p/9795832.html