用python 4行搞定基数排序

from random import randint  
              
def main():                 
    A = [randint(1, 99999999) for _ in xrange(9999)]  
    for k in xrange(8):     
        S = [ [] for _ in xrange(10)]  
        for j in A:         
            S[j / (10 ** k) % 10].append(j)  
        A = [a for b in S for a in b]  
    for i in A:             
        print i

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原文地址：https://www.cnblogs.com/wishchin/p/9200229.html