hdu 1213 How Many Tables 解题报告

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213

     有关系(直接或间接均可)的人就坐在一张桌子,我们要统计的是最少需要的桌子数。

     并查集的入门题,什么优化都无用到就可以直接过。实质上就是统计总共有多少个不相交的集合。比较可恶的是,题目中 There will be a blank line between two cases 是骗人的!!!

  

 1 #include <iostream>
 2 using namespace std;
 3 
 4 const int maxn = 1000 + 5;
 5 int p[maxn], rank[maxn];
 6 
 7 int find(int x)
 8 {
 9     while (x != p[x])
10         x = p[x];
11     return x;
12 }
13 
14 void merge(int i, int j)
15 {
16     int x = find(i);
17     int y = find(j);
18     if (x > y)
19         p[y] = x;
20     else
21         p[x] = y;
22 }
23 
24 int main()
25 {
26     int a, b, i, t, m, n, refusals;
27     while (scanf("%d", &t) != EOF)
28     {
29         while (t--)
30         {
31             scanf("%d%d", &n, &m);
32             for (i = 1; i <= n; i++)
33                 p[i] = i;
34             for (i = 0; i < m; i++)
35             {
36                 scanf("%d%d", &a, &b);    
37                 merge(a, b);
38             }
39             for (refusals = 0, i = 1; i <= n; i++)
40                 if (p[i] == i)
41                     refusals++;
42             printf("%d\n", refusals);
43         }
44     }
45     return 0;
46 } 
原文地址:https://www.cnblogs.com/windysai/p/3307717.html