牛客2018校招 1. 拼多多 最大乘积

第一题：主要看一下输入输出.

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Comparator;

public class Main{
    public static void main(String[] args) throws IOException{
        InputStreamReader ir = new InputStreamReader(System.in);
        BufferedReader bf = new BufferedReader(ir);
        int n = Integer.parseInt(bf.readLine());
        String[] str = bf.readLine().split(" ");
        int[] nums = new int[str.length];
        for (int i = 0;i < nums.length; i++)
            nums[i] = Integer.parseInt(str[i]);
        System.out.println(Main.method(nums));
    }
    
    public static long method(int[] arr){
        int max1 = Integer.MIN_VALUE, max2 = Integer.MIN_VALUE, max3 = Integer.MIN_VALUE;
        int min1 = Integer.MAX_VALUE, min2 = Integer.MAX_VALUE;
        for (int n : arr){
            if (n > max1){
                max3 = max2;
                max2 = max1;
                max1 = n;
            }else if(n > max2){
                max3 = max2;
                max2 = n;
            }else if(n > max3){
                max3 = n;
            }
            
            if (n < min1){
                min2 = min1;
                min1 = n;
            }else if(n < min2){
                min2 = n;
            }
        }
        return Math.max( (long)max1*max2*max3, (long)max1*min1*min2 );
    }
}