sizeof(class)---类的字节长度

上代码:

// test_max.cpp : 定义控制台应用程序的入口点。

#include "stdafx.h" #include <iostream> using namespace std; class A { public: void fun1(){}; void fun2(){}; }; class B { public: void fun1(int i=10){}; void fun2(){}; public: char c; int a; }; class C { public: void fun1(){}; virtual void fun2(){}; }; class D { public: void fun1(){}; virtual void fun2(){}; virtual void fun3(){}; public: int a; }; int main() { A a; A* a1=new A(); cout<<"A's size is "<<sizeof(A)<<"."<<endl; cout<<"B's size is "<<sizeof(B)<<"."<<endl; cout<<"C's size is "<<sizeof(C)<<"."<<endl; cout<<"D's size is "<<sizeof(D)<<"."<<endl; cout<<"A's object size is "<<sizeof(a)<<"."<<endl; cout<<"A's object pointer size is "<<sizeof(a1)<<"."<<endl; system("pause"); return 0; }


注:VS2010 Win7 32位

总结:

(1)仅仅含有函数成员的类的大小是1(不知为啥,希望大神解释)

(2)含有数据成员的类的大小为数据成员字节对齐后所占空间大小
(3)含有虚函数类,虚函数所占的空间为四字节(一个指向虚函数表的指针,与虚函数的个数无关)

(4)对象与类所占的空间同样

(5)类对象指针的大小为4

原文地址:https://www.cnblogs.com/wgwyanfs/p/7190364.html