hibernate报错Unknown integral data type for ids : java.lang.String

package com.model;
// Generated 2016-10-27 14:02:17 by Hibernate Tools 4.3.1.Final

/**
 * CmDept generated by hbm2java
 */
public class CmDept/* implements java.io.Serializable */{

    private String id;
    private String deptName;

    public CmDept() {
    }

    public CmDept(String id) {
        this.id = id;
    }

    public CmDept(String id, String deptName) {
        this.id = id;
        this.deptName = deptName;
    }

    public String getId() {
        return this.id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getDeptName() {
        return this.deptName;
    }

    public void setDeptName(String deptName) {
        this.deptName = deptName;
    }

}
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated 2016-10-27 14:40:22 by Hibernate Tools 3.5.0.Final -->
<hibernate-mapping>
    <class name="com.model.CmDept" table="CM_DEPT">
        <id name="id" type="java.lang.String">
            <column name="ID" />
            <generator class="sequence">
                <param name="sequence">cm_sequence_dept</param>
            </generator>
        </id>
        <property name="deptName" type="java.lang.String">
            <column name="DEPTNAME" />
        </property>
    </class>
</hibernate-mapping>

以上代码是报错的代码 ! ! !

由于是使用的反向工程建表, 在设计表结构的时候将几个表的id设置成了varchar2型, 导致反向工程生成的实体类的主键id的类型变成String了, 所以当HibernateTemplate在插入数据的时候不认识了, 所以报了这个错误, 从新修改一遍表结构, 将oracle数据库的主键改成number, 将实体类中的id改成Bigdecimal, 还记得要重新生成一遍*.hbm.xml文件, 问题解决

原文地址:https://www.cnblogs.com/wgbs25673578/p/6019814.html