冒泡排序

package lianxi;
import java.util.*;
public class Maopaopaixu {

public static void main(String[] args) {
    //输入数字  并把数字插入数组中
    Scanner shu=new Scanner(System.in); 
    System.out.println("请输入10个数字:");
    int ary[]=new int[10];
    for (int i = 0; i < 10; i++) 
    {
        int b = shu.nextInt();
        ary[i]=b; 
        
    }
    //显示一下数组中的元素  看是否与输入对应
    for (int i = 0; i <ary.length; i++)
    {
        System.out.print("ary["+i+"]="+ary[i]+"  ");
        
    }    
       System.out.println();
   //从大到小排序    每循环一次输出ary[j]-ary[9]的最大值
    for (int j = 0; j < 10; j++) 
    {
        for (int k = j; k <9; k++) 
        {
            if(ary[j]<ary[k+1])
            {
                int m=0;
                m=ary[j];
                ary[j]=ary[k+1];
                ary[k+1]=m;
            }
            
            
        }
          System.out.print(ary[j]+"  ");
    }
      
    
    }

}

原文地址:https://www.cnblogs.com/wenwen123/p/5477203.html