Celery ValueError: not enough values to unpack (expected 3, got 0)的解决方案

Celery ValueError: not enough values to unpack (expected 3, got 0)的解决方案

背景

最近因项目需要,学习任务队列Celery的用法,跟着官网写Demo,出现如题错误,最终在github的Issues里找到解决办法,记录如下。

场景还原

本地环境如下:

  • Windows 10
  • Python 3.5.2
  • Celery 4.1.0

我是跟着这个前人翻译的中文文档敲的Demo。

代码tasks.py

from celery import Celery

app = Celery('tasks', broker='redis://:xxxx@xxx.xxx.xxx.xx:6379/0')

@app.task
def add(x, y):
    return x + y1234567

执行worker

celery -A tasks worker --loglevel=info1

输出:

 -------------- celery@kong9wei11 v4.1.0 (latentcall)
---- **** -----
--- * ***  * -- Windows-10-10.0.14393-SP0 2018-01-12 19:01:39
-- * - **** ---
- ** ---------- [config]
- ** ---------- .> app:         tasks:0x157fd248550
- ** ---------- .> transport:   redis://:**@114.67.225.0:6379/0
- ** ---------- .> results:     disabled://
- *** --- * --- .> concurrency: 4 (prefork)
-- ******* ---- .> task events: OFF (enable -E to monitor tasks in this worker)
--- ***** -----
 -------------- [queues]
                .> celery           exchange=celery(direct) key=celery


[tasks]
  . tasks.add

[2018-01-12 19:01:40,029: INFO/MainProcess] Connected to redis://:**@114.67.225.0:6379/0
[2018-01-12 19:01:40,130: INFO/MainProcess] mingle: searching for neighbors
[2018-01-12 19:01:40,550: INFO/SpawnPoolWorker-1] child process 9048 calling self.run()
[2018-01-12 19:01:40,557: INFO/SpawnPoolWorker-2] child process 9028 calling self.run()
[2018-01-12 19:01:40,578: INFO/SpawnPoolWorker-3] child process 13064 calling self.run()
[2018-01-12 19:01:40,611: INFO/SpawnPoolWorker-4] child process 9856 calling self.run()
[2018-01-12 19:01:41,693: INFO/MainProcess] mingle: all alone
[2018-01-12 19:01:42,212: INFO/MainProcess] celery@xx ready.1234567891011121314151617181920212223242526

调用任务代码manager.py

from tasks import add

add.delay(4, 4)123

执行

python manager.py1

然后worker里报错:

[2018-01-12 19:08:15,545: INFO/MainProcess] Received task: tasks.add[5d387722-5389-441b-9b01-a619b93b4702]
[2018-01-12 19:08:15,550: ERROR/MainProcess] Task handler raised error: ValueError('not enough values to unpack (expected 3, got 0)',)
Traceback (most recent call last):
  File "d:programmingsoftwarepython35libsite-packagesilliardpool.py", line 358, in workloop
    result = (True, prepare_result(fun(*args, **kwargs)))
  File "d:programmingsoftwarepython35libsite-packagesceleryapp	race.py", line 525, in _fast_trace_task
    tasks, accept, hostname = _loc
ValueError: not enough values to unpack (expected 3, got 0)12345678

解决:

原网页:Unable to run tasks under Windows

看别人描述大概就是说win10上运行celery4.x就会出现这个问题,解决办法如下,原理未知:

先安装一个``eventlet`

pip install eventlet1

然后启动worker的时候加一个参数,如下:

celery -A <mymodule> worker -l info -P eventlet1

然后就可以正常的调用了。

运行

python manage.py1

worker里输出:

[2018-01-12 19:35:33,640: INFO/MainProcess] Received task: tasks.add[3f9b5255-60a2-4a08-96b6-38f5fbc31543]
[2018-01-12 19:35:33,640: INFO/MainProcess] Task tasks.add[3f9b5255-60a2-4a08-96b6-38f5fb
原文地址:https://www.cnblogs.com/wenqiangit/p/10577345.html