抄写作业

//例题9.1//
#include<stdio.h>
int main()
{struct Student
  {long int num;    //定义长整形num// 
  char name[20];    //定义字符数组name,记住:当没有初始化时,字符数组中数不能空// 
  char sex;     
  char addr[20];   
  }a={10101,"Li Lin",'M',"123 Beijing Road"};      //给定义的数都初始化,注意:字符初始化要有单引号,字符串初始化要有双引号//
  printf("NO.:%ld
name:%s
sex:%c
address:%s
",a.num,a.name,a.sex,a.addr);   //输出的变量要对应相应的格式符// 
  return 0;
}
NO.:10101
name:Li Lin
sex:M
address:123 Beijing Road

--------------------------------
Process exited after 0.4356 seconds with return value 0
请按任意键继续. . .

  

//例题9.2//
#include<stdio.h>
int main()
{struct student
	{  int num;               
	   char name[20];         
	   float score;
	}student1,student2;
	scanf("%d%s%f",&student1.num,&student1.name,&student1.score);       //输入学生1,2的各项值,再输入中一定得加&// 
	scanf("%d%s%f",&student2.num,&student2.name,&student2.score);
	printf("The higher score is:
");
	if(student1.score>student2.score)                                    //用双重if语句来判断学生们的大小比较// 
	   printf("%d  %s  %6.2f
",student1.num,student1.name,student1.score);
	else if(student1.score<student2.score)   
	   printf("%d  %s  %6.2f
",student2.num,student2.name,student2.score);
	else
	{  printf("%d  %s  %6.2f
",student1.num,student1.name,student1.score);
	   printf("%d  %s  %6.2f
",student2.num,student2.name,student2.score);
	   }   
    return 0;
}
10101 ww 88.5
10103 qq 44.1
The higher score is:
10101  ww   88.50

--------------------------------
Process exited after 16.54 seconds with return value 0
请按任意键继续. . .

  

//例题9.3//
#include<string.h>
#include<stdio.h>
struct person
{char name[20];
 int count;
}leader[3]={"Li",0,"Zhang",0,"Sun",0};
int main()
{int i,j;
 char leader_name[20];
 for(i=1;i<=10;i++)
    {scanf("%s",leader_name);
       for(j=0;j<3;j++)                                                  //用包含for循环选出投票数// 
         if(strcmp(leader_name,leader[j].name)==0)leader[j].count++;
	}
    printf("
Result:
");
    for(i=0;i<3;i++)
         printf("%5s:%d
",leader[i].name,leader[i].count);
   return 0;      
} 
Li
Zhang
Li
Li
Sun
Zhang
Zhang
Zhang
Sun
Li

Result:
   Li:4
Zhang:4
  Sun:2

--------------------------------
Process exited after 62.49 seconds with return value 0
请按任意键继续. . .

  

//例题9.4//
#include<stdio.h>
struct Student 
{  int num;
   char name[20];
   float score;
};
int main() 
{struct Student stu[5]={{10101,"Zhang",78},{10103,"Wang",98.5},{10106,"Li",86}, {10108,"Ling",73.5},{10110,"Sun",100}};  
 struct Student temp;  
 const int n=5;  
 int i,j,k;  
 printf("The order is:
");  
 for(i=0;i<n-1;i++)  
     {k=i;   
      for(j=i+1;j<n;j++)
	     if(stu[j].score>stu[k].score) 
		 k=j;
		 temp=stu[k]; 
		 stu[k]=stu[i];
	     stu[i]=temp;
	 }   
	 for(i=0;i<n;i++)   
	      printf("%6d %8s %6.2f
",stu[i].num,stu[i].name,stu[i].score);
 printf("
"); 
 return 0; 
} 
The order is:
 10110      Sun 100.00
 10103     Wang  98.50
 10106       Li  86.00
 10101    Zhang  78.00
 10108     Ling  73.50


--------------------------------
Process exited after 0.1495 seconds with return value 0
请按任意键继续. . .

  

//例题9.5//
#include<stdio.h>
#include<string.h> 
int main() 
{struct Student  
    {long num;
	 char name[20];
	 char sex; 
	 float score; 
	};struct Student stu_1;
	  struct Student *p; 
	  p=&stu_1; 
	  stu_1.num=10101; 
	  strcpy(stu_1.name,"Li Lin"); 
	  stu_1.sex='M';  
	  stu_1.score=89.5;  
	  printf("No.:%ld
name:%s
sex:%c
score:%5.1f
",stu_1.num,stu_1.name,stu_1.sex,stu_1.score);  
	  printf("
");  
	  printf("No.:%ld
name:%s
sex:%c
score:%5.1f
",(*p).num,(*p).name,(*p).sex,(*p).score);  
  return 0; 
} /

  

No.:10101
name:Li Lin
sex:M
score: 89.5

No.:10101
name:Li Lin
sex:M
score: 89.5

--------------------------------
Process exited after 0.1335 seconds with return value 0
请按任意键继续. . .  
//例题9.6//
#include<stdio.h> 
struct Student 
{int num;  
 char name[20]; 
 char sex;
 int age; 
};struct Student stu[3]={{10101,"Li Lin",'M',18},{10102,"Zhang Fang",'M',19},{10104,"Wang Min",'F',20}}; 
int main() 
{struct Student *p;  
 printf("No.    Name                sex age
"); 
 for(p=stu;p<stu+3;p++) 
 printf("%5d %-20s %2c %4d
",p->num,p->name,p->sex,p->age);
 return 0; 
}
No.    Name                sex age
10101 Li Lin                M   18
10102 Zhang Fang            M   19
10104 Wang Min              F   20

--------------------------------
Process exited after 0.1049 seconds with return value 0
请按任意键继续. . .

  

//例题9.7//
#include<stdio.h>
#define N 3 
struct Student 
{int num;
 char name[20]; 
 float score[3]; 
 float aver; 
}; 
int main() 
{void input(struct Student stu[]); 
 struct Student max(struct Student stu[]);
 void print(struct Student stud);  
 struct Student stu[N],*p=stu;  
 input(p);  
 print(max(p));  
 return 0; 
} 
void input(struct Student stu[])
{int i;
 printf("请输入各学生的信息:学号、姓名、三门课成绩:
");
 for(i=0;i<N;i++) 
     {scanf("%d %s %f %f %f",&stu[i].num,&stu[i].name,&stu[i].score[0],&stu[i].score[1],&stu[i].score[2]);
	  stu[i].aver=(stu[i].score[0]+stu[i].score[1]+stu[i].score[2])/3.0;
	 } 
}  
struct Student max(struct Student stu[])
{int i,m=0;
 for(i=0;i<N;i++)
     if(stu[i].aver>stu[m].aver)m=i;
	 return stu[m]; 
}
void print(struct Student stud) 
{printf("
成绩最高的学生是:
");  
 printf("学号:%d
姓名:%s
三门成绩:%5.1f,%5.1f,%5.1f
平均成绩:%6.2f
",stud.num,stud.name,stud.score[0],stud.score[1],stud.score[2],stud.aver);
}
请输入各学生的信息:学号、姓名、三门课成绩:
22 ww 44 77 88
33 qq 44 77 55
44 ee 66 33 11

成绩最高的学生是:
学号:22
姓名:ww
三门成绩: 44.0, 77.0, 88.0
平均成绩: 69.67

--------------------------------
Process exited after 24.56 seconds with return value 0
请按任意键继续. . .

  

总结:C语言是极易弄错误的一门课,因此需要我们细心查看,要注意标点括号,要查阅出错时程序给的错误提示,并思考出现这种错误的原因,然后逐     层修改。

         

原文地址:https://www.cnblogs.com/wengweng/p/6681872.html