wenbao与回文串dp

http://oj.jxust.edu.cn/problem.php?id=1432

 1 #include <iostream>
 2 #include <string.h>
 3 using namespace std;
 4 
 5 char str[1009];
 6 int dp[1009][1009];
 7 
 8 int main(){
 9     int t;
10     scanf("%d", &t);
11     while(t--){
12         scanf("%s", str+1);
13         int len = strlen(str+1);
14         memset(dp, 0, sizeof(dp));
15         for(int i = 1; i <= len; ++i){
16             for(int j = i-1; j > 0; --j){
17                 if(str[i] == str[j]){
18                     dp[j][i] = dp[j+1][i-1];
19                 }else{
20                     dp[j][i] = min(dp[j+1][i-1]+2, min(dp[j+1][i]+1, dp[j][i-1]+1));
21                 }
22             }
23         }
24         printf("%d
", dp[1][len]);
25     }
26     return 0;
27 }

只有不断学习才能进步!

原文地址:https://www.cnblogs.com/wenbao/p/7448403.html