JS 功能函数


//*************************************
//
读取Url中参数的函数
//
*************************************
function getUrlParameter(seekParameter) {
var url = location.href;
var parameters = url.substr(url.indexOf("?") + 1);
var parameterItems = parameters.split("&");
var parameterName;
var parameterVar = "";
for (i in parameterItems) {
parameterName
= parameterItems[i].split("=")[0];
parameterVar
= parameterItems[i].split("=")[1];
if (parameterName == seekParameter) {
return (parameterVar);
}
}
return "";
}
//*************************************
//
修改Url中参数的函数
//
*************************************
function setUrlParam(url, param, v) {
var re = new RegExp("(\\\?|&)" + param + "=([^&]+)(&|$)", "i");
var m = url.match(re);
if (m) {
return (url.replace(re, function ($0, $1, $2) { return ($0.replace($2, v)); }));
}
else {
if (url.indexOf('?') == -1)
return (url + '?' + param + '=' + v);
else
return (url + '&' + param + '=' + v);
}
}
 

1、返回无重复的新数组(就是原数组删除重复的元素)
<script type="text/javascript">
    Array.prototype.strip = function(){
        if(this.length < 2) [this[0]]||[];
        var arr = [];
        for(var i = 0;i < this.length;i ++){
            arr.push(this.splice(i--,1));
            for(var j=0;j<this.length;j++){
                if(this[j] == arr[arr.length-1]){
                    this.splice(j--,1);
                }
            }
        }
        return arr;
    }
    var arr=["123a",85,4,,54,"123a",85,8,8,1,2,5,4,7,8,54,"44"];
    alert(arr.strip());
</script>
2、返回被删元素组成的新数组
<script type="text/javascript">
    Array.prototype.strip=function(){
        if(this.length<2) return [];
        var arr=[];
        var del=[];
        for(var i=0;i<this.length;i++){
            arr.push(this.splice(i--,1));
            for(var j=0;j<this.length;j++){
                if(this[j]==arr[arr.length-1]){
                    del.push(this.splice(j--,1));
                }
            }
        }
        return del;
    }
    var arr=["123a",85,4,,54,"123a",85,8,8,1,2,5,4,7,8,54,"44"];
    alert(arr.strip());
</script>

原文地址:https://www.cnblogs.com/weekend001/p/2023862.html