判断0-N之间出现1的次数

            Console.WriteLine("请输入截止数字?退出请输入y");
            string input = Console.ReadLine();
            int n = Convert.ToInt32(input);
            int count = 0; //计数
            for (int i = 0; i <= n; i++)
            {
                string str = i.ToString();//要匹配的字符串
                string pattern="1"; //要匹配的正则表达式模式
                MatchCollection matches = Regex.Matches(str, pattern);  //正则表达式匹配验证
                count += matches.Count;  //获得匹配数量,加到计数上,
                //foreach (Match NextMatch in matches) //遍历获得数量也行,不过效率低
                //{
                //    count++;
                //}
            }
            Console.WriteLine("在0-{0}中1出现了"+count+"",input);
原文地址:https://www.cnblogs.com/wdmhn/p/3166917.html