Form,选择并转移导航菜单

1、代码实例

<!DOCTYPE html>
<html>
<head>
    <title>选择并转移导航菜单</title>
    <meta charset="utf-8">
</head>
<body>
     <form method="post" action="select.html">
         <select id="newLocation">
             <option selected>select a topic</option>
             <option value="script01.html">javascript</option>
             <option value="script02.html">jquery</option>
             <option value="script03.html">jquery mobile</option>
             <option value="script04.html">html5</option>
             <option value="script05.html">css3</option>
         </select>
     </form>
</body>
</html>

<script type="text/javascript">
    window.onload = init;
    window.unload = function(){};
    function init(){
        document.getElementById("newLocation").selectedIndex = 0;
        console.log(document.getElementById("newLocation").options);
        document.getElementById("newLocation").onchange = jumpPage;
    }
    function jumpPage(){
        var newLoc = document.getElementById("newLocation");
        var newPage = newLoc.options[newLoc.selectedIndex].value;
        if(newPage != ""){
            window.location = newPage;
        }
    }
</script>

2、重点分析:

  2.1、window.onunload = function(){}:

    onunload 事件在用户退出页面时发生;

    

  2.2、selectedIndex:

           selectedIndex 属性可设置或返回下拉列表中被选选项的索引号。

           注释:若允许多重选择,则仅会返回第一个被选选项的索引号。

  2.3、options:

    删除被选中的项
    objSelect.options[objSelect.selectedIndex] = null;

    增加项
    objSelect.options[objSelect.length] = new Option("你好","hello");

    修改所选择中的项
    objSelect.options[objSelect.selectedIndex] = new Option("你好","hello");

    得到所选择项的文本
    objSelect.options[objSelect.selectedIndex].text;

    得到所选择项的值
    objSelect.options[objSelect.selectedIndex].value; 

原文地址:https://www.cnblogs.com/wdlhao/p/5468304.html