P2399 non hates math

P2399 non hates math
将分数化成小数的模拟题，把循环减掉就可以了。
1.1(234)
*10^4==11234.234
*10^1==11.234
9999*(1.1（234))==11223
所以
(1.1（234))==11223/9999
  1 #include<iostream>
  2 #include<cstdio>
  3 #include<queue>
  4 #include<algorithm>
  5 #include<cmath>
  6 #include<ctime>
  7 #include<cstring>
  8 #define inf 2147483647
  9 #define For(i,a,b) for(register long long i=a;i<=b;i++)
 10 #define p(a) putchar(a)
 11 #define g() getchar()
 12 //by war
 13 //2017.10.23
 14 using namespace std;
 15 char a[10100];
 16 long long len;
 17 long long fenzi,fenmu,zi,mu;
 18 long long g,s;
 19 bool flag;
 20 
 21 void in(long long &x)
 22 {
 23     long long y=1;
 24     char c=g();x=0;
 25     while(c<'0'||c>'9')
 26     {
 27     if(c=='-')
 28     y=-1;
 29     c=g();
 30     }
 31     while(c<='9'&&c>='0')x=x*10+c-'0',c=g();
 32     x*=y;
 33 }
 34 void o(long long x)
 35 {
 36     if(x<0)
 37     {
 38         p('-');
 39         x=-x;
 40     }
 41     if(x>9)o(x/10);
 42     p(x%10+'0');
 43 }
 44 
 45 long long gcd(long long a,long long b)
 46 {
 47     return (b==0?a:gcd(b,a%b));
 48 }
 49 
 50 long long ksm(long long a,long long b)
 51 {
 52     if(b==0)
 53     return 1;
 54     while(b%2==0)
 55     {
 56         b>>=1;
 57         a=a*a;
 58     }
 59     long long r=1;
 60     while(b>0)
 61     {
 62         if(b%2==1)
 63         r=r*a;
 64         b>>=1;
 65         a=a*a;
 66     }
 67     return r;
 68 }
 69 
 70 int main()
 71 {
 72     cin>>a;
 73     len=strlen(a);
 74     For(i,0,len-1)
 75     if(a[i]!='.')
 76     fenzi=fenzi*10+a[i]-'0';    
 77     else
 78     {
 79     s=i+1;
 80     break;    
 81     }
 82     fenmu=ksm(10,len-s);    
 83     For(i,s,len-1)
 84     {
 85     if(a[i]=='(')
 86     {
 87     flag=true;
 88     mu=ksm(10,i-s);    
 89     zi=fenzi;
 90     }
 91     if(a[i]!='('&&a[i]!=')')
 92     {
 93     fenzi=fenzi*10+a[i]-'0';
 94     if(!flag)
 95     zi=zi*10+a[i]-'0';
 96     }    
 97     }
 98     if(!flag)
 99     {
100         zi=0;
101         mu=0;
102     }
103     else
104     {
105     fenmu/=100;    
106     }
107     fenzi-=zi;
108     fenmu-=mu;
109     g=gcd(fenzi,fenmu);
110     fenzi/=g;
111     fenmu/=g;
112     o(fenzi),p('/'),o(fenmu);
113      return 0;
114 }