shell脚本,编写1个弹出式菜单的shell程序并实现其简单的菜单功能。

[root@localhost wyb]# cat zonghe.sh 
#!/bin/bash
#zonghe
usage(){
case $choice in
1)
read -p "please input the old file and new file : " old_file new_file
cp -r $old_file $new_file
if [ $? -eq 0 ];then
    echo "success!" >&2
fi    
     sleep 2
;;


2)
read -p "please input the file and newname : " file newname
mv $file $newname
if [ $? -eq 0 ] ;then
    echo "success!" >&2
fi    
sleep 2
;;


3)
read -p "please input the file or dir you wanna del : " filename
rm -rf $filename
if [ $? -eq 0 ];then
    echo "success!" >&2
fi    
sleep 2
;;


4)
read -p "please input the file you wanna find : " file
find / -name $file
if [ $? -eq 0 ];then
    echo "success!" >&2
fi
sleep 2    
;;

5)
exit 0
;;

*)
;;




esac

}


while :

do

cat<<EOF
 *************************************
*                MENU                  *

*   1.copy                 2.rename    *

*   3.remove               4.find      *

*                 5.exit              *


 *************************************
EOF
 

read -p "please enter your choice : " choice

usage

done
原文地址:https://www.cnblogs.com/wangyuebo/p/5818626.html