Python_二分法

 1 l = [1,2,5,7,10,31,44,47,56,99,102,130,240]
 2 def search_binary(l,item):
 3     mid_index = len(l) // 2
 4     if len(l) == 1:
 5         if l[0] == item:
 6             print('find it')
 7         else:
 8             print('not exists')
 9     if len(l) > 1:
10         if l[mid_index] > item:
11             l = l[:mid_index]
12             search_binary(l,item)
13         elif l[mid_index] < item:
14             l = l[mid_index:]
15             search_binary(l,item)
16         else:
17             print('find it')
18 search_binary(l,32)
l = [1,2,5,7,10,31,44,47,56,99,102,130,240]
def search_binary(l,item):
mid_index = len(l) // 2
if len(l) == 1:
if l[0] == item:
print('find it')
else:
print('not exists')
if len(l) > 1:
if l[mid_index] > item:
l = l[:mid_index]
search_binary(l,item)
elif l[mid_index] < item:
l = l[mid_index:]
search_binary(l,item)
else:
print('find it')
search_binary(l,32)
原文地址:https://www.cnblogs.com/wangmengzhu/p/7263359.html