1042/72 n!

Problem Description
Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N!
 

 

Input
One N in one line, process to the end of file.
 


Output
For each N, output N! in one line.
 


Sample Input
1
2
3
 


Sample Output
2
6
 1 #include <iostream>
 2 #include <algorithm>
 3 #include <stdio.h>
 4 #include <math.h>
 5 #include <string.h>
 6 #include <time.h>
 7 using namespace std;
 8 int a[10001];
 9 int main()
10 {
11     int n,sum,i,j,k;
12     while(~scanf("%d",&n))
13     {
14         k=a[0]=1;sum=0;
15         for(i=n;i>1;i--)
16         {
17             for(j=0;j<k;j++)
18             {
19                 a[j]=a[j]*i+sum;
20                 sum=a[j]/100000;
21                 a[j]=a[j]%100000;
22 
23             }
24             while(sum)
25             {
26                 a[k++]=sum%100000;
27                 sum=sum/100000;
28             }
29         }
30         cout<<a[k-1];
31         for(int i=k-2;i>=0;i--)
32         printf("%05d",a[i]);
33         cout<<endl;
34     }
35     return 0;
36 }
View Code

这个题有两个知识点:

1.数值型高精度

2.补零操作(重点)

原文地址:https://www.cnblogs.com/wang-ya-wei/p/5263302.html