面试题62 序列化二叉树

题目描述

请实现两个函数,分别用来序列化和反序列化二叉树
 1 /*
 2 struct TreeNode {
 3     int val;
 4     struct TreeNode *left;
 5     struct TreeNode *right;
 6     TreeNode(int x) :
 7             val(x), left(NULL), right(NULL) {
 8     }
 9 };
10 */
11 typedef TreeNode node;
12 typedef TreeNode* pnode;
13 typedef int* pint;
14 class Solution {
15     vector<int> buf;
16     void dfs(pnode p){
17         if(!p) buf.push_back(0x23333);
18         else{
19             buf.push_back(p -> val);
20             dfs(p -> left);
21             dfs(p -> right);
22         }
23     }
24     pnode dfs2(pint& p){
25         if(*p == 0x23333){
26             ++p;
27             return NULL;
28         }
29         pnode res = new node(*p);
30         ++p;
31         res -> left = dfs2(p);
32         res -> right = dfs2(p);
33         return res;
34     }
35 public:
36     char* Serialize(TreeNode *p) {
37         buf.clear();
38         dfs(p);
39         int *res = new int[buf.size()];
40         for(unsigned int i = 0; i < buf.size(); ++i) res[i] = buf[i];
41         return (char*)res;
42     }
43     TreeNode* Deserialize(char *str) {
44         int *p = (int*)str;
45         return dfs2(p);
46     }
47 };
原文地址:https://www.cnblogs.com/wanderingzj/p/5375738.html