LeetCode 58 Length of Last Word

LeetCode  58 Length of Last Word

int lengthOfLastWord(char* s) {
    int length=0,falg=0;
    int n=strlen(s);
    if(n<=0)
        return 0;
    for(int i=n;i>=1;i--)
    {
        if(falg==1 && s[i-1]==' ')
            break;
        if(s[i-1]!=' ')
        {
            falg=1;
            length++;
        }
    }
    return length;
}
原文地址:https://www.cnblogs.com/walker-lee/p/4997975.html